Keyframes
Question
What is the length of the longest dimension (length, width, or height) of the telephone, measured in centimeters? Answer the spatial reasoning question about the 3D scene. For multiple-choice, answer with the option's letter directly. For numerical questions, answer with a single number.
Ground truth 53
SpatialClaw 50 0.90
Agent wins

No-tool Baseline

Score 0.00

To determine the length of the longest dimension of the telephone, we can use surrounding objects for scale. In frames 6, 7, and 8, a white, wall-mounted telephone is visible on the wall above a dresser and next to a standard electrical outlet.

  1. Reference Object (Electrical Outlet): A standard North American duplex electrical outlet is approximately 11.5 cm (4.5 inches) in height.
  2. Comparison: By comparing the telephone to the outlet in frame 7, the telephone's height (its longest dimension) appears to be roughly 1.5 to 2 times the height of the outlet.
  3. Calculation: $11.5\text{ cm} \times 1.7 \approx 19.5\text{ cm}$ or $11.5\text{ cm} \times 2 \approx 23\text{ cm}$.
  4. Standard Dimensions: Typical basic wall-mounted telephones of this style generally have a height ranging from 20 to 25 cm (approximately 8 to 10 inches).

Based on the visual scale relative to the electrical outlet and standard product dimensions, the longest dimension of the telephone is approximately 20 cm.

20

Single-pass code

Score 0.30
Purpose
Locate, segment, and measure the telephone's longest dimension in 3D space.
Reasoning
1. **Visual Identification**: The telephone is visible on the wall in `InputImages[6]` and `InputImages[7]`. 2. **Grounding**: I will use `vlm.locate` to get a bounding box for the telephone in `InputImages[6]`. 3. **Segmentation**: I'll use `tools.SAM3.segment_image_by_box` to get a precise mask of the telephone. 4. **3D Reconstruction**: I'll use `tools.Reconstruct.Reconstruct` on all available frames to build a 3D model of the scene. 5. **Measurement**: * Extract the 3D points corresponding to the telephone mask using `seg.get_masked_points`. * Calculate the pair-wise distance between all points in the point cloud (or use a bounding box if the point cloud is dense and well-aligned) to find the maximum distance, which represents the longest dimension. * Convert this distance from meters to centimeters.
Next Goal
Execute the measurement pipeline and return the result.
Code
import numpy as np

# 1. Locate the telephone in InputImages[6]
img_idx = 6
img = InputImages[img_idx]
W, H = img.width, img.height
bbox_norm = vlm.locate(img, "Give the bounding box (x1, y1, x2, y2) in 0-1000 normalized scale for the telephone on the wall. Reply with ONLY the numbers.")
print(f"BBox norm: {bbox_norm}")

# Parse bbox
try:
    x1, y1, x2, y2 = map(int, bbox_norm.replace(',', ' ').split())
except ValueError:
    # Fallback if VLM returns something else
    ReturnAnswer("Could not parse bbox")

# Convert to pixels
px1, py1, px2, py2 = tools.Geometry.normalized_to_pixel((x1, y1, x2, y2), W, H)
bbox = [px1, py1, px2, py2]

# 2. Segment the telephone
seg = tools.SAM3.segment_image_by_box(img, bbox, label="telephone")
fi = seg.frame_indices[0]

# Verify segmentation
mask = seg.get_mask(frame=fi, object=0)
area = mask.sum()
print(f"Mask area: {area} pixels")
show([img, seg.visualize(fi)])

# 3. Reconstruct the scene
recon = tools.Reconstruct.Reconstruct(InputImages)

# 4. Get 3D points and compute longest dimension
points = seg.get_masked_points(recon, frame=fi, object=0)
if points is None or len(points) == 0:
    ReturnAnswer("No 3D points found for telephone")

# Filter points by confidence if possible, but get_masked_points usually does that or we can use recon.points.confidence
# Since get_masked_points is a helper, let's just use the points.
# To find the longest dimension, we find the max distance between any two points in the cloud.
# For efficiency and robustness, we can use the diameter of the point cloud.
# With a small number of points, we can just do a brute force distance matrix.

if len(points) > 1000:
    # Subsample for speed if too many points
    indices = np.random.choice(len(points), 1000, replace=False)
    points = points[indices]

# Compute distance matrix
diff = points[:, np.newaxis, :] - points[np.newaxis, :, :]
dist_matrix = np.linalg.norm(diff, axis=2)
max_dist_m = np.max(dist_matrix)

# Convert to cm
max_dist_cm = max_dist_m * 100
print(f"Longest dimension: {max_dist_cm:.2f} cm")

ReturnAnswer(max_dist_cm)
Output
[VLM Q | locate] Before answering, first check whether what the question describes is clearly visible in the provided image(s). If it is absent or ambiguous, reply EXACTLY `Not visible` on its own line (optionally followed by one short line explaining what you saw instead) — do NOT return coordinates in that case. Only if the requested target is clearly and unambiguously present, answer the request below.

Request: Give the bounding box (x1, y1, x2, y2) in 0-1000 normalized scale for the telephone on the wall. Reply with ONLY the numbers.
[VLM A | locate] 764 10 832 296
BBox norm: 764 10 832 296
Mask area: 3438 pixels
 [image: show_0001] 
Longest dimension: 72.10 cm
[ReturnAnswer] Answer submitted: 72.09644913673401
show_0001
Final answer
72.09644913673401

Structured tool-call

Score 0.00
Plan

Task Analysis The objective is to determine the length of the longest dimension (length, width, or height) of a telephone in centimeters. This is a metric measurement task requiring 3D spatial reasoning. The target variable is a scalar value in centimeters. The coordinate system needed is world-space 3D to obtain absolute metric dimensions.

Information Needs

  1. Object Identification: Precise location and visual confirmation of the "telephone" in the images.
  2. 3D Geometry: A metric 3D reconstruction of the scene to convert pixel-space observations into real-world measurements (meters).
  3. Precise Segmentation: Accurate masks of the telephone across multiple frames to capture its full 3D extent.
  4. Metric Scale: The metric_scale from the reconstruction to ensure the final value is in absolute units.

Computation Plan

  1. Visual Identification: Use show(InputImages[0], InputImages[4], InputImages[7]) to identify the telephone and determine which frames provide the best views of its full extent.
  2. 3D Reconstruction: Perform a full scene reconstruction using recon = tools.Reconstruct.Reconstruct(InputImages).
  3. Object Segmentation:
    • Attempt to segment the telephone using seg = tools.SAM3.segment_image_by_text(InputImages[0], "telephone").
    • If text segmentation is empty or inaccurate (verified via seg.visualize(fi) and show()), use vlm.locate on a clear frame to get a bounding box, then segment using tools.SAM3.segment_image_by_box.
    • Ensure segmentation is performed across all frames where the telephone is visible to maximize the captured 3D point cloud.
  4. Mask Verification: Call show() on the original images and the seg.visualize(fi) overlays to confirm the masks tightly bound the telephone without including background or other objects.
  5. 3D Point Extraction:
    • For each frame fi in seg.frame_indices, extract the world-space points belonging to the telephone using points_3d = seg.get_masked_points(recon, frame=fi, object=0).
    • Aggregate all points from all frames into a single global point cloud for the telephone.
  6. Dimension Calculation:
    • Compute the distance between the two most distant points in the aggregated 3D point cloud (the diameter of the point set) using tools.Geometry.euclidean_distance or by calculating the maximum extent of the point cloud's oriented bounding box.
    • This maximum distance represents the longest dimension of the object.
  7. Unit Conversion: Convert the resulting distance from meters to centimeters by multiplying by 100.

Verification

  1. Mask Integrity: Visually verify that the segmentation masks are consistent across frames and do not "leak" into the table or surrounding environment.
  2. Reconstruction Sanity: Check the recon.metric_scale and the general layout of the reconstructed scene via recon.render_bev(masks=seg) to ensure the 3D structure is plausible.
  3. Multi-frame Consistency: Compare the calculated longest dimension using points from a single frame versus the aggregated point cloud to ensure stability.
  4. Physical Sanity Check: Compare the final result (e.g., 15-30 cm for a typical telephone) against common sense. If the result is an order of magnitude off (e.g., 2 meters), re-examine the reconstruction and masks.

Fallbacks

  • If the reconstruction is too noisy for a precise measurement, I will use vlm.ask_with_thinking to identify a known reference object in the scene (e.g., a standard pen, a coin, or a credit card) and estimate the telephone's size relative to that object.
  • If the telephone is only partially visible, I will calculate the dimension of the visible portion and note the limitation.

CHECKLIST

[
  {"priority": "HIGH", "description": "Verify that the segmented object is indeed the telephone and not another nearby object"},
  {"priority": "HIGH", "description": "Visually confirm that the SAM3 masks are tight and accurate across multiple frames"},
  {"priority": "MEDIUM", "description": "Check that the 3D point cloud for the telephone is dense enough to represent its true boundaries"},
  {"priority": "LOW", "description": "Sanity-check the final centimeter value against typical real-world telephone dimensions"}
]
Step 0
LLM · Tool Call
Purpose
Identify the telephone and determine which frames provide the best views.
Reasoning
I need to visually locate the telephone in the scene to ensure I segment the correct object. Based on a quick scan of the key frames, the telephone appears to be wall-mounted, visible in the later frames (especially frames 6 and 7) next to the dresser.
Next Goal
Confirm the location of the telephone and its visibility in specific frames.
Tool Call
{
  "tool": "show",
  "args": {
    "image": [
      "InputImages[6]",
      "InputImages[7]"
    ]
  }
}
Execute
Output
 [image: show_0001] 
show_0001
Step 1
LLM · Tool Call
Purpose
Create a 3D reconstruction of the scene to obtain metric measurements.
Reasoning
To measure the physical dimensions of the telephone in centimeters, I need a 3D point cloud with a known metric scale. Reconstructing the scene from the available frames will provide this.
Next Goal
Segment the telephone in the reconstructed scene.
Tool Call
{
  "tool": "tools.Reconstruct.Reconstruct",
  "args": {
    "frames": "InputImages"
  }
}
Step 2
LLM · Tool Call
Purpose
Segment the telephone using text-based segmentation.
Reasoning
I will attempt to automatically segment the telephone in the image where it is most clearly visible (frame 7) using the `segment_image_by_text` tool. If this succeeds, I can use the mask to extract 3D points.
Next Goal
Verify the segmentation mask and then extract 3D points.
Tool Call
{
  "tool": "tools.SAM3.segment_image_by_text",
  "args": {
    "image": "InputImages[7]",
    "prompt": "telephone",
    "label": "telephone"
  }
}
Step 3
LLM · Tool Call
**Purpose**: Verify the accuracy of the telephone segmentation mask. **Reasoning**: Before proceeding to 3D point extraction, I must ensure that the SAM3 mask tightly and accurately covers the telephone without including background elements. I will visualize the mask overlay on the original image. **Next Goal**: Extract 3D points for the telephone from the reconstruction. **Tool Call (translated)**: ```python result_3 = show([InputImages[7], result_2.visualize(result_2.frame_indices[0])]) ```
Step 4
LLM · Tool Call
Purpose
Verify the accuracy of the telephone segmentation mask.
Reasoning
Before calculating dimensions, I must ensure the mask tightly bounds the telephone and doesn't include background noise or other objects. I'll visualize the mask overlay on the original image.
Next Goal
Extract 3D points for the telephone if the mask is correct.
Tool Call
{
  "tool": "show",
  "args": {
    "image": [
      "InputImages[7]",
      "result_2.visualize(7)"
    ]
  }
}
Execute
Output
 [image: show_0002] 
show_0002
Step 5
LLM · Tool Call
Tool Call
{
  "tool": "feedback.ask_vlm",
  "args": {
    "visual_input": "InputImages[7]",
    "question": "Give the bounding box (x1, y1, x2, y2) in 0-1000 normalized scale for the telephone. Reply with ONLY the numbers."
  }
}
Step 7
LLM · Tool Call
Purpose
Obtain the 2D bounding box of the telephone in frame 7 to estimate its physical dimensions.
Reasoning
Since I cannot directly compute the diameter of a 3D point cloud with the available tools, I will use the pinhole camera model. By finding the pixel dimensions of the telephone and its depth from the reconstruction, I can calculate its real-world size in meters.
Next Goal
Get the depth of the telephone and the camera intrinsics to perform the metric conversion.
Tool Call
{
  "tool": "tools.Mask.bounding_box",
  "args": {
    "mask": "result_2.get_mask(frame=7, object=0)"
  }
}
Step 8
LLM · Tool Call
**Purpose**: Extract the 3D centroid of the telephone to determine its distance from the camera. **Reasoning**: The 3D centroid provides a representative depth (Z) for the object. Combined with the pixel dimensions from the bounding box, I can estimate the length of the longest dimension. **Next Goal**: Calculate the physical size of the telephone using the depth and camera intrinsics. **Tool Call (translated)**: ```python result_8 = result_2.get_centroid_3d(recon=result_1, frame=7, object=0) ```
Step 9
LLM · Tool Call
Purpose
Calculate the physical width of the telephone in meters.
Reasoning
By extracting the 3D world coordinates of the top-left and top-right corners of the telephone's bounding box from the reconstruction, I can compute the Euclidean distance between them to find the width.
Next Goal
Calculate the physical height of the telephone.
Tool Call
{
  "tool": "tools.Geometry.euclidean_distance",
  "args": {
    "p1": "result_1.points[7][result_7[1], result_7[0]]",
    "p2": "result_1.points[7][result_7[1], result_7[2]]"
  }
}
Step 10
LLM · Tool Call
Purpose
Calculate the physical height of the telephone in meters.
Reasoning
I have calculated the width by finding the distance between the top-left and top-right corners of the bounding box in 3D world space. Now, I will calculate the height by finding the distance between the top-left and bottom-left corners of the bounding box in 3D world space.
Next Goal
Compare width and height to find the longest dimension and convert it to centimeters.
Tool Call
{
  "tool": "tools.Geometry.euclidean_distance",
  "args": {
    "p1": "result_1.points[7][result_7[1], result_7[0]]",
    "p2": "result_1.points[7][result_7[3], result_7[0]]"
  }
}
Step 12
LLM · Tool Call
Purpose
Retrieve the numerical values of the calculated width and height.
Reasoning
I have computed the width (`result_9`) and height (`result_10`) of the telephone in meters, but I do not have the actual numerical values. By plotting them using `tools.Graph.plot`, the resulting `VisualFeedback.description` will provide the maximum value among them, which corresponds to the longest dimension in meters.
Next Goal
Convert the maximum dimension from meters to centimeters and provide the final answer.
Tool Call
{
  "tool": "tools.Graph.plot",
  "args": {
    "values": [
      "result_9",
      "result_10"
    ],
    "title": "Telephone Dimensions"
  }
}
Step 13
LLM · Tool Call
**Purpose**: Inspect the plot of the telephone's dimensions to retrieve the numerical values for width and height. **Reasoning**: I have computed the width and height in meters and plotted them. By visualizing the plot, I can read the values from the axes or the accompanying description to determine which dimension is longer and what its value is. **Next Goal**: Convert the longest dimension to centimeters and provide the final answer. **Tool Call (translated)**: ```json {"tool": "show", "args": {"image": "result_12"}} ```
Step 14
LLM · Tool Call
Purpose
Retrieve the numerical values of the telephone's dimensions from the plot summary.
Reasoning
I have calculated the width and height in meters (`result_9` and `result_10`), and plotted them in `result_12`. The `VisualFeedback` object's description contains the summary statistics (min, max, mean), which will give me the exact numerical values of the dimensions.
Next Goal
Extract the maximum dimension from the plot description, convert it to centimeters, and return the final answer.
Tool Call
{
  "tool": "show",
  "args": {
    "image": "result_12"
  }
}
Execute
Output
 [image: show_0003] 
show_0003
Step 15
LLM · Tool Call
Purpose
Calculate the final answer for the longest dimension of the telephone.
Reasoning
From the plot in `result_12`, I can see that the two measured dimensions are approximately 0.083 meters (width) and 0.198 meters (height). The longest dimension is therefore the height, which is approximately 0.198 meters. Converting this to centimeters: $0.198 \text{ m} \times 100 = 19.8 \text{ cm}$. Rounding to the nearest whole number, we get 20 cm, which is a typical size for a wall-mounted telephone.
Next Goal
Return the final answer.
Tool Call
{
  "tool": "ReturnAnswer",
  "args": {
    "answer": 20
  }
}
Execute
Output
[ReturnAnswer] Answer submitted: 20
Answer
20

SpaceTools

Score 0.30
Tool decision

🛠️ Decided to use 1 tool(s)

tool_calls
[
  {
    "name": "vlm__detect_one",
    "arguments": {
      "image_index": 7,
      "obj_name": "telephone"
    }
  }
]
Tool call

⚡ Executing vlm__detect_one...

tool_name
vlm__detect_one
arguments
{
  "image_index": 7,
  "obj_name": "telephone"
}
Tool result

✅ vlm__detect_one completed (with generated image)

tool_name
vlm__detect_one
result
Detected 1 instance(s) of 'telephone': [(0.602, 0.10800000000000001)] Use $telephone_detections to reference them.
Synthesizing

🧠 Synthesizing results from 1 tool(s)...

Tool decision

🛠️ Decided to use 1 tool(s)

tool_calls
[
  {
    "name": "sam2__segment_from_point",
    "arguments": {
      "image_index": 7,
      "x": 0.602,
      "y": 0.108
    }
  }
]
Tool call

⚡ Executing sam2__segment_from_point...

tool_name
sam2__segment_from_point
arguments
{
  "image_index": 7,
  "x": 0.602,
  "y": 0.108
}
Tool result

✅ sam2__segment_from_point completed (with generated image)

tool_name
sam2__segment_from_point
result
Segmented object at normalized coords (0.602, 0.108) with IoU score: 0.763. Use $segmentation_mask (boolean array, 968x1296) to reference it.
Synthesizing

🧠 Synthesizing results from 1 tool(s)...

Tool decision

🛠️ Decided to use 1 tool(s)

tool_calls
[
  {
    "name": "depth_estimator__estimate_depth_with_pointcloud",
    "arguments": {
      "image_index": 7
    }
  }
]
Tool call

⚡ Executing depth_estimator__estimate_depth_with_pointcloud...

tool_name
depth_estimator__estimate_depth_with_pointcloud
arguments
{
  "image_index": 7
}
Tool result

✅ depth_estimator__estimate_depth_with_pointcloud completed (with generated image)

tool_name
depth_estimator__estimate_depth_with_pointcloud
result
Generated 1296x968 depth map and 1,254,528 3D points. Depth range in point cloud: 0.88m to 2.33m (mean: 1.24m). Use $depth_map (numpy array, 968x1296), $point_cloud (numpy array, 1254528x3) and $focal...
Synthesizing

🧠 Synthesizing results from 1 tool(s)...

Tool decision

🛠️ Decided to use 1 tool(s)

tool_calls
[
  {
    "name": "bounding_box__compute_bbox",
    "arguments": {
      "focal_length_px": 1234.5,
      "mask": "$segmentation_mask",
      "point_cloud": "$point_cloud"
    }
  }
]
Tool call

⚡ Executing bounding_box__compute_bbox...

tool_name
bounding_box__compute_bbox
arguments
{
  "focal_length_px": 1234.5,
  "mask": "$segmentation_mask",
  "point_cloud": "$point_cloud"
}
Tool result

✅ bounding_box__compute_bbox completed

tool_name
bounding_box__compute_bbox
result
Oriented bounding box computed from 8389/1254528 points.Corners in 3D: [[0.104, -0.165, 1.376], [0.114, -0.484, 1.265], [0.17, -0.17, 1.398], [0.09, -0.178, 1.414], [0.167, -0.503, 1.324], [0.157, -0....
Synthesizing

🧠 Synthesizing results from 1 tool(s)...

Reasoning

The longest dimension of the telephone is approximately 33.8 centimeters (based on the computed oriented bounding box extent of 0.338 meters).

33.8

Final answer

The longest dimension of the telephone is approximately 33.8 centimeters (based on the computed oriented bounding box extent of 0.338 meters).

33.8

Final response

The longest dimension of the telephone is approximately 33.8 centimeters (based on the computed oriented bounding box extent of 0.338 meters).

33.8

SpatialClaw

Score 0.90
Plan

Task Analysis

The goal is to determine the length of the longest dimension (length, width, or height) of a telephone in centimeters. This is a metric 3D measurement task. The target object is a "telephone." The result must be a single numerical value in centimeters. The coordinate system required is world-space 3D to obtain real-world metric dimensions.

Information Needs

  1. Object Identification: Locate the telephone in the provided frames.
  2. 3D Scene Geometry: A metric 3D reconstruction of the scene to convert pixel/depth data into real-world meters.
  3. Precise Segmentation: A high-quality mask of the telephone to isolate its 3D points from the background.
  4. Point Cloud Analysis: The set of 3D world coordinates corresponding to the telephone to calculate its physical extent.

Computation Plan

  1. Initial Identification:

    • Use show(InputImages[0], InputImages[len(InputImages)//2], InputImages[-1]) to identify which frames best capture the telephone and its overall shape.
    • Use vlm.ask_with_thinking on these frames to confirm the telephone's presence and describe its orientation.
  2. 3D Reconstruction:

    • Perform reconstruction on all available frames: recon = tools.Reconstruct.Reconstruct(InputImages). This provides the metric_scale and the points map.
  3. Target Segmentation:

    • Attempt segmentation using text: seg = tools.SAM3.segment_image_by_text(InputImages[best_frame], "telephone").
    • If the text prompt fails (empty mask or wrong object), use vlm.locate to get a bounding box in normalized coordinates for the telephone in InputImages[best_frame].
    • Convert the box to pixels using tools.Geometry.normalized_to_pixel and segment using tools.SAM3.segment_image_by_box.
  4. Mask Verification:

    • Visually verify the mask: show([InputImages[best_frame], seg.visualize(seg.frame_indices[0])]).
    • Programmatically check the mask area to ensure it is non-zero.
  5. Dimension Calculation:

    • Extract the 3D world points for the telephone: points_3d = seg.get_masked_points(recon, frame=seg.frame_indices[0], object=0).
    • Filter the points based on recon.points.confidence to remove outliers.
    • To find the longest dimension, compute the maximum Euclidean distance between any two points in the point cloud: $\max |p_i - p_j|$ for all $p_i, p_j$ in points_3d.
    • Alternatively, compute the axis-aligned bounding box (AABB) if the object is aligned with world axes, but the max-pair distance is more robust to rotation.
  6. Unit Conversion:

    • The reconstruction output is in meters. Multiply the maximum distance by 100 to convert the result to centimeters.

Verification Checklist

[
  {"priority": "HIGH", "description": "Verify that the SAM3 mask accurately and tightly covers the telephone without including background or other objects."},
  {"priority": "HIGH", "description": "Confirm that the reconstruction is stable and the metric scale is applied correctly."},
  {"priority": "MEDIUM", "description": "Check the calculated dimension against common sense (e.g., a telephone should typically be between 10cm and 30cm)."},
  {"priority": "MEDIUM", "description": "Verify the point cloud for outliers that could artificially inflate the 'longest dimension' calculation."}
]

Verification

  • Cross-Validation: Compare the 3D centroid and extent across at least two different frames to ensure consistency in the measurement.
  • Visual Sanity Check: Render a BEV plot recon.render_bev(masks=seg) to see if the object's footprint in the 3D world matches the expected proportions of a telephone.
  • Diagnostic: If the calculated size is physically impossible (e.g., 2 meters), I will re-examine the metric_scale and the segmentation mask for leakage into the background.

Fallbacks

  • If the telephone is too small or the reconstruction is too noisy for precise point-cloud measurement, I will use vlm.ask_with_thinking to identify a known reference object in the scene (e.g., a standard credit card, a coin, or a known piece of furniture) and estimate the telephone's size relative to that object.
  • If the telephone is only partially visible, I will use the visible portion to estimate the total length based on the object's known typical proportions.
Step 0
LLM
Purpose
Identify the telephone in the provided images and confirm its location.
Reasoning
I need to find the telephone to perform segmentation and measurement. Looking at the key frames, a telephone handset appears to be mounted on the wall in the last few frames (InputImages[6] and InputImages[7]), above the dresser. I will inspect these frames and use the VLM to confirm.
Next Goal
Use `vlm.ask_with_thinking` to confirm the telephone's presence and identify the best frame for segmentation.
Execute
Code
# Inspecting frames where the telephone is likely visible
show([InputImages[0], InputImages[4], InputImages[7]])

# Confirming the telephone's presence and location
confirmation = vlm.ask_with_thinking(InputImages[6:], "Is there a telephone in these images? If so, which frame shows it most clearly and where is it located (e.g., on the wall, on a table)?")
print(confirmation)
Output
 [image: show_0001] 
[VLM Q | thinking] Is there a telephone in these images? If so, which frame shows it most clearly and where is it located (e.g., on the wall, on a table)?
[VLM A | thinking] Yes, there is a telephone. It is most clearly visible in frame 1, where it is located on the wall.
Yes, there is a telephone. It is most clearly visible in frame 1, where it is located on the wall.
show_0001
Step 1
LLM
Purpose
Perform 3D reconstruction of the scene and segment the telephone.
Reasoning
To measure the telephone's dimensions in centimeters, I need a metric 3D reconstruction. I will reconstruct the scene using all available frames. Then, I will segment the telephone in `InputImages[7]`, as it is clearly visible and well-positioned. I'll try text-based segmentation first.
Next Goal
Verify the segmentation mask and then extract the 3D points to calculate the longest dimension.
Execute
Code
# 1. Perform 3D reconstruction
recon = tools.Reconstruct.Reconstruct(InputImages)

# 2. Segment the telephone in the best frame (InputImages[7])
# Using text-based segmentation first
best_frame = InputImages[7]
seg = tools.SAM3.segment_image_by_text(best_frame, "telephone")

# 3. Programmatic check of the mask
fi = seg.frame_indices[0]
for i, label in enumerate(seg.labels):
    mask = seg.get_mask(frame=fi, object=i)
    area = mask.sum()
    print(f"Object {i} ({label}) area: {area} pixels")

# Visual verification
vis = seg.visualize(fi)
show([best_frame, vis])
Output
Object 0 (telephone) area: 3150 pixels
 [image: show_0002] 
show_0002
Step 2
LLM
Purpose
Calculate the longest dimension of the telephone in centimeters.
Reasoning
I have a valid segmentation mask and a 3D reconstruction. I will extract the 3D world points corresponding to the telephone mask, filter them by confidence to remove outliers, and then compute the maximum distance between any two points (the diameter of the point cloud) to find the longest dimension.
Next Goal
Return the final answer.
Execute
Code
import numpy as np
from scipy.spatial.distance import pdist

# 1. Get the mask and the local index of the frame
fi = seg.frame_indices[0]
local_idx = recon.frame_indices.index(fi)
mask = seg.get_mask(frame=fi, object=0)

# 2. Extract 3D points and confidence for the frame
points_all = recon.points[fi]  # (H, W, 3)
conf_all = recon.points.confidence[local_idx]  # (H, W)

# 3. Filter points by mask and confidence
# Use a confidence threshold to remove noise (e.g., 0.5)
valid_mask = mask & (conf_all > 0.5)
points_filtered = points_all[valid_mask]

print(f"Number of filtered points: {len(points_filtered)}")

if len(points_filtered) < 2:
    # Fallback: use all points in the mask if confidence filter is too aggressive
    points_filtered = points_all[mask]
    print(f"Fallback: using all masked points. Count: {len(points_filtered)}")

# 4. Compute the maximum distance between any two points (Diameter)
if len(points_filtered) > 0:
    # pdist computes pairwise distances between observations in n-dimensional space.
    # For 3150 points, pdist is efficient.
    distances = pdist(points_filtered)
    max_dist_m = np.max(distances)
    max_dist_cm = max_dist_m * 100
    print(f"Longest dimension: {max_dist_m:.4f} m = {max_dist_cm:.2f} cm")
else:
    max_dist_cm = None
    print("No points found for the telephone.")

# Sanity check: A typical wall phone handset is 20-30cm.
# If the result is wildly different, I'll investigate.
Output
Number of filtered points: 3150
Longest dimension: 1.1690 m = 116.90 cm
Condense · step 3
**Purpose**: Refine the segmentation to isolate the telephone handset and exclude the cord. **Reasoning**: [errored — condensed] **Next Goal**: [errored — condensed] **Code**: ```python # 1. Get a precise bounding box for the telephone handset only # InputImages[7] is the best frame handset_box_norm = vlm.locate(InputImages[7], "Give the bounding box (x1, y1, x2, y2) in 0-1000 normalized scale for the telephone handset (the part you hold to your ear, excluding the cord). Reply with ONLY the numbers.") print(f"Handset box (norm): {handset_box_norm}") # 2. Convert normalized coordinates to pixels W, H = InputImages[7].width, InputImages[7].height import ast # Handle potential string response from VLM try: box_coords = ast.literal_eval(handset_box_norm) # <-- ERROR # ValueError: could not convert string to float: '567 10 630 165' ```
Step 4
LLM
Purpose
Refine the segmentation to isolate the telephone handset and re-calculate its longest dimension.
Reasoning
The previous measurement (116.9 cm) was erroneously high because the segmentation mask included the telephone cord. I will now use a precise bounding box for the handset only, segment it, and then compute the maximum distance between its 3D points.
Next Goal
Calculate the final longest dimension in centimeters and return the answer.
Execute
Code
# 1. Parse the bounding box from the previous VLM response
# handset_box_norm = '567 10 630 165'
box_coords = [int(x) for x in handset_box_norm.split()]
px1, py1, px2, py2 = tools.Geometry.normalized_to_pixel(box_coords, W, H)
print(f"Pixel box: {px1, py1, px2, py2}")

# 2. Segment the handset using the box
seg_handset = tools.SAM3.segment_image_by_box(InputImages[7], [px1, py1, px2, py2], "handset")

# 3. Verify the mask
fi_h = seg_handset.frame_indices[0]
vis_h = seg_handset.visualize(fi_h)
show([InputImages[7], vis_h])

# 4. Calculate the longest dimension of the handset
local_idx_h = recon.frame_indices.index(fi_h)
mask_h = seg_handset.get_mask(frame=fi_h, object=0)
points_all_h = recon.points[fi_h]
conf_all_h = recon.points.confidence[local_idx_h]

# Filter by mask and confidence
valid_mask_h = mask_h & (conf_all_h > 0.5)
points_filtered_h = points_all_h[valid_mask_h]

if len(points_filtered_h) < 2:
    points_filtered_h = points_all_h[mask_h]

if len(points_filtered_h) > 1:
    distances_h = pdist(points_filtered_h)
    max_dist_m_h = np.max(distances_h)
    max_dist_cm_h = max_dist_m_h * 100
    print(f"Refined longest dimension: {max_dist_m_h:.4f} m = {max_dist_cm_h:.2f} cm")
else:
    max_dist_cm_h = None
    print("Insufficient points found for the handset.")
Output
Pixel box: (435.45599999999996, 5.76, 483.84000000000003, 95.04)
 [image: show_0003] 
Refined longest dimension: 1.1544 m = 115.44 cm
show_0003
Step 5
LLM
Purpose
Diagnose the cause of the physically impossible telephone measurement by checking the metric scale using a reference object (the dresser).
Reasoning
The calculated telephone length (~115 cm) is far too large. This indicates either a failure in the 3D reconstruction's metric scale or severe depth errors (point bleeding) for the telephone. I will segment the dresser, which is a large, stable object, and calculate its height. Since a standard dresser is typically 70-90 cm tall, this will reveal if the reconstruction's global scale is incorrect.
Next Goal
Segment the dresser, calculate its height, and use this to determine if I need to adjust the scale or use a different estimation method.
Execute
Code
# 1. Segment the dresser in InputImages[7]
seg_dresser = tools.SAM3.segment_image_by_text(InputImages[7], "dresser")

# 2. Verify dresser mask
fi_d = seg_dresser.frame_indices[0]
vis_d = seg_dresser.visualize(fi_d)
show([InputImages[7], vis_d])

# 3. Calculate dresser height
local_idx_d = recon.frame_indices.index(fi_d)
mask_d = seg_dresser.get_mask(frame=fi_d, object=0)
points_all_d = recon.points[fi_d]
conf_all_d = recon.points.confidence[local_idx_d]

valid_mask_d = mask_d & (conf_all_d > 0.5)
points_filtered_d = points_all_d[valid_mask_d]

if len(points_filtered_d) > 1:
    # Height is the difference between max and min Y (since +Y is up)
    y_coords = points_filtered_d[:, 1]
    dresser_height_m = np.max(y_coords) - np.min(y_coords)
    dresser_height_cm = dresser_height_m * 100
    print(f"Dresser height: {dresser_height_m:.4f} m = {dresser_height_cm:.2f} cm")
else:
    dresser_height_cm = None
    print("Insufficient points for dresser.")
Output
 [image: show_0004] 
Dresser height: 1.0015 m = 100.15 cm
show_0004
Step 6
LLM
Purpose
Estimate the telephone handset's length using the dresser as a metric reference.
Reasoning
The 3D point cloud for the telephone is unreliable (showing 115 cm) due to depth bleeding into the wall, while the dresser's 3D height (100 cm) is plausible. Since both objects are at a similar depth from the camera in `InputImages[7]`, the ratio of their pixel heights is a reliable proxy for the ratio of their real-world lengths. I will calculate the pixel height of both the dresser and the handset, then use the dresser's real height to find the handset's length.
Next Goal
Calculate the pixel heights, compute the ratio, and return the final answer.
Execute
Code
# 1. Get bounding boxes for both objects in InputImages[7]
dresser_box_norm = vlm.locate(InputImages[7], "Give the bounding box (x1, y1, x2, y2) in 0-1000 normalized scale for the dresser. Reply with ONLY the numbers.")
handset_box_norm = vlm.locate(InputImages[7], "Give the bounding box (x1, y1, x2, y2) in 0-1000 normalized scale for the telephone handset (the part you hold to your ear). Reply with ONLY the numbers.")

print(f"Dresser box (norm): {dresser_box_norm}")
print(f"Handset box (norm): {handset_box_norm}")

# 2. Convert to pixel heights
W, H = InputImages[7].width, InputImages[7].height

def get_pixel_height(norm_box_str):
    coords = [int(x) for x in norm_box_str.split()]
    # normalized_to_pixel returns [x1, y1, x2, y2]
    px_coords = tools.Geometry.normalized_to_pixel(coords, W, H)
    return abs(px_coords[3] - px_coords[1]) # y2 - y1

dresser_px_h = get_pixel_height(dresser_box_norm)
handset_px_h = get_pixel_height(handset_box_norm)

print(f"Dresser pixel height: {dresser_px_h}")
print(f"Handset pixel height: {handset_px_h}")

# 3. Calculate real length using the ratio
# Dresser real height was measured as 100.15 cm
dresser_real_h = 100.15
handset_real_h = (handset_px_h / dresser_px_h) * dresser_real_h

print(f"Estimated handset length: {handset_real_h:.2f} cm")

# Final Answer based on this calculation
ReturnAnswer(round(handset_real_h))
Output
[VLM Q | locate] Before answering, first check whether what the question describes is clearly visible in the provided image(s). If it is absent or ambiguous, reply EXACTLY `Not visible` on its own line (optionally followed by one short line explaining what you saw instead) — do NOT return coordinates in that case. Only if the requested target is clearly and unambiguously present, answer the request below.

Request: Give the bounding box (x1, y1, x2, y2) in 0-1000 normalized scale for the dresser. Reply with ONLY the numbers.
[VLM A | locate] 366 340 886 1000
[VLM Q | locate] Before answering, first check whether what the question describes is clearly visible in the provided image(s). If it is absent or ambiguous, reply EXACTLY `Not visible` on its own line (optionally followed by one short line explaining what you saw instead) — do NOT return coordinates in that case. Only if the requested target is clearly and unambiguously present, answer the request below.

Request: Give the bounding box (x1, y1, x2, y2) in 0-1000 normalized scale for the telephone handset (the part you hold to your ear). Reply with ONLY the numbers.
[VLM A | locate] 566 11 631 341
Dresser box (norm): 366 340 886 1000
Handset box (norm): 566 11 631 341
Dresser pixel height: 380.15999999999997
Handset pixel height: 190.08
Estimated handset length: 50.08 cm
[ReturnAnswer] Answer submitted: 50
Answer
50
Evaluation
Ground truth: 53 · Agent: 50